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Hello group members,

I have just acquired the book "Varga Chakra", which is very useful

and helps me to understand the underlying principles behind the

different methods of varga construction (Brahma varga =

straightforward harmonics as in Western astrology; Shiva vargas =

vargas with breaks or jumps, etc)

However, in Sanjay Rath's chapter on the shastyamsa (p. 134), I

don't understand why he says first (which of course I knew) that

there the shastyamsa is one-sixtieth division of a sign measuring

30' of arc, and then goes on to say that "There are a total of 1800

shastyamsa in the zodiac with sixty in each sign. As a time measure,

the average time taken for Lagna to traverse a shastyamsa is 48

seconds. Thus the smallest measure of time used by Parasara is 48

seconds when this shastyamsa shall change."

Surely, 12 signs x 60 divisions = 720 (not 1800), and the average

time taken for a change of lagna in shastyamsa is therefore 2

minutes. Am I right, or have I misunderstood something?

Thank you for any clarification

Graham Fox

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Dear Graham

 

Yes, there are 60 Shastiamsas per Rasi, thus there are 720. The

shastiamsa lagna changes for every two minutes approximately.

best wishes

partha

 

 

vedic astrology, "Graham Fox"

<fox.graham@w...> wrote:

>

> Hello group members,

> I have just acquired the book "Varga Chakra", which is very useful

> and helps me to understand the underlying principles behind the

> different methods of varga construction (Brahma varga =

> straightforward harmonics as in Western astrology; Shiva vargas =

> vargas with breaks or jumps, etc)

> However, in Sanjay Rath's chapter on the shastyamsa (p. 134), I

> don't understand why he says first (which of course I knew) that

> there the shastyamsa is one-sixtieth division of a sign measuring

> 30' of arc, and then goes on to say that "There are a total of 1800

> shastyamsa in the zodiac with sixty in each sign. As a time

measure,

> the average time taken for Lagna to traverse a shastyamsa is 48

> seconds. Thus the smallest measure of time used by Parasara is 48

> seconds when this shastyamsa shall change."

> Surely, 12 signs x 60 divisions = 720 (not 1800), and the average

> time taken for a change of lagna in shastyamsa is therefore 2

> minutes. Am I right, or have I misunderstood something?

> Thank you for any clarification

> Graham Fox

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Dear Partha,

Thank you. I can now see that Sanjay Rath must be confusing the

shastyamsa with the nadiamsa: in the D-150, there are indeed 1800

divisions in the whole zodiac, and each the lagna does take 48" to

cross a nadiamsa. But as far as I know, no version of Parasara uses

or mentions the D-150.

Best wishes

Graham

 

this vedic astrology, "V.Partha sarathy"

<partvinu@g...> wrote:

>

> Dear Graham

>

> Yes, there are 60 Shastiamsas per Rasi, thus there are 720. The

> shastiamsa lagna changes for every two minutes approximately.

> best wishes

> partha

>

>

> vedic astrology, "Graham Fox"

> <fox.graham@w...> wrote:

> >

> > Hello group members,

> > I have just acquired the book "Varga Chakra", which is very

useful

> > and helps me to understand the underlying principles behind the

> > different methods of varga construction (Brahma varga =

> > straightforward harmonics as in Western astrology; Shiva vargas

=

> > vargas with breaks or jumps, etc)

> > However, in Sanjay Rath's chapter on the shastyamsa (p. 134), I

> > don't understand why he says first (which of course I knew) that

> > there the shastyamsa is one-sixtieth division of a sign

measuring

> > 30' of arc, and then goes on to say that "There are a total of

1800

> > shastyamsa in the zodiac with sixty in each sign. As a time

> measure,

> > the average time taken for Lagna to traverse a shastyamsa is 48

> > seconds. Thus the smallest measure of time used by Parasara is

48

> > seconds when this shastyamsa shall change."

> > Surely, 12 signs x 60 divisions = 720 (not 1800), and the

average

> > time taken for a change of lagna in shastyamsa is therefore 2

> > minutes. Am I right, or have I misunderstood something?

> > Thank you for any clarification

> > Graham Fox

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