Guest guest Posted August 30, 2004 Report Share Posted August 30, 2004 For those of you that are interested in the physics of electrostim here is the physics beyond symmetrical and asymmetrical waves. As you can see this as nothing to do with Net-DC Unfortunately I cant email the figures but i will have them in my book. Alon An oscillating voltage wave form applied to a device is able to produce instantaneous power equal to the square of the current times the resistance of the circuit where the power is expended (P=I2 R). Based on this, it can be derived that the average power (Pav) expended in a circuit for a sine wave (alternating current) is the sum of all incremental ordinates squared time the resistance (the same applies to voltage V since V= I R, and R is a constant). By means of mathematical calculus, the result can be demonstrated to be: Paw = 1/2 R Im2 (R= resistance of circuit, Im = maximum ordinate of the sine wave). Assume now that the same resistance is calculated in a Direct Current (DC) circuit until the power dissipated is equal to that dissipated by the resistance in an AC circuit. We can explain this as RI2=1/2 RI2m or I=1 divided by square root of 2 times Im; or 0.707 Im. This is called the effective current. Following the same method for a triangle wave (fig b) it can be demonstrated that Ieff =1 divided by square root of 3 times Im; or Ieff =0.578 Im. Now if we have an alternating wave as shown in fig c (approximation of real output curves of acupuncture simulators) in which a=0.578 b, the effective value of the triangular side of the wave will be equal to that of the square side (equivalent to DC input). The DC voltage equivalent of the alternating wave shown (asymmetric biphasic square wave) will be zero. The energy produced (power during a lapse of time) will be the sum of the one produced by the square wave, plus the one produced by the triangular wave. Quote Link to comment Share on other sites More sharing options...
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