Guest guest Posted August 23, 2005 Report Share Posted August 23, 2005 Dear Manoshi, My answer here is based functional SD. Now another scenario is this. Lets take X = Ve, Y = Me, Z = Sa. Assume X and Z are not in 1:7. Now X is SD to Y (Ve is SD to Me) and Y is SD to Z (Me is SD to Sa). Now Ve is not Functional SD to Sa however in this exception Ve is NSD to Sa i.e natural Samdharmi. So please keep this in mind also when u study. Cheers !!! Ash , " ashsam73 " <ashsam73> wrote: > Dear Manoshi, > No. > Cheers !!! > Ash > > , " Manoshi > Chatterjee " <khallopapa> wrote: > > Dear Ash, > > > > Thanx for all the information on samadharmi planets, but my > question > > was... > > > > let there be three planets X, Y, and Z. > > > > if X=Y ( = be SD) > > and Y=Z > > > > Is X=Z too? > > > > means, if Y can give results for X > > and if Z can give results for Y > > will Z will give results for X too? I thnik NO but still was > > clarifying. > > > > --Manoshi > > > > , " ashsam73 " > > <ashsam73> wrote: > > > Dear Manoshi, > > > > > > Here is an old mail I had written on 4:10. > > > > > > > /message/5886 > > > > > > Cheers !!! > > > Ash > > > > > > , " Manoshi > > Chatterjee " > > > <khallopapa> wrote: > > > > Dear Ash and others, > > > > > > > > say Mercury is samdharmee to Venus and moon is also > samadharmee > > to > > > > venus. will venus act as a samadharmi to Mercury, I mean if > > mercury > > > > is giving " move " , then Venus might give move ( I am > > considerining > > > only > > > > SD factor to give results here), will Moon also will have the > > > > capability to give move ( based on SD factor)? > > > > > > > > --Manoshi Quote Link to comment Share on other sites More sharing options...
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